45fan.com - 路饭网

搜索: 您的位置主页 > 网络频道 > 阅读资讯:Python开发简单hangman游戏的实例代码分享

Python开发简单hangman游戏的实例代码分享

2015-07-21 20:13:54 来源:www.45fan.com 【

Python开发简单hangman游戏的实例代码分享

本文实例讲述了Python实现的简单hangman游戏。分享给大家供大家参考。具体如下:

#!/usr/bin/env python
import random 
import cPickle 
class Hangman(object):
 '''A simple hangman game that tries to improve your vocabulary a bit '''
 def __init__(self):
  # the variables used, this is not necessary
  self.dumpfile = ''  #the dictionary file
  self.dictionary = {}  #the pickled dict
  self.words = []   #list of words used
  self.secret_word = '' #the 'key'
  self.length = 0   #length of the 'key'
  self.keys = []   #inputs that match the 'key'
  self.used_keys = []  #keys that are already used
  self.guess = ''   #player's guess
  self.mistakes = 0  #number of incorrect inputs
  return self.load_dict()
 #insert some random hints for the player
 def insert_random(self, length):
  randint = random.randint
  # 3 hints
  if length >= 7: hint = 3
  else: hint = 1
  for x in xrange(hint):
    a = randint(1, length - 1)
    self.keys[a-1] = self.secret_word[a-1]
 def test_input(self):
  #if the guessed letter matches
  if self.guess in self.secret_word:
   indexes = [i for i, item in enumerate(self.secret_word) if item == self.guess]
   for index in indexes:
    self.keys[index] = self.guess
    self.used_keys.append(self.guess)
    print "used letters ",set(self.used_keys),'\n'
  #if the guessed letter didn't match
  else:
   self.used_keys.append(self.guess)
   self.mistakes += 1
   print "used letters ",set(self.used_keys),'\n'
 # load the pickled word dictionary and unpickle them 
 def load_dict(self):
  try :
   self.dumpfile = open("~/python/hangman/wordsdict.pkl", "r")
  except IOError:
   print "Couldn't find the file 'wordsdict.pkl'"
   quit()
  self.dictionary = cPickle.load(self.dumpfile)
  self.words = self.dictionary.keys()
  self.dumpfile.close()
  return self.prepare_word()
 #randomly choose a word for the challenge
 def prepare_word(self):
  self.secret_word = random.choice(self.words)
  #don't count trailing spaces
  self.length = len(self.secret_word.rstrip())
  self.keys = ['_' for x in xrange(self.length)]
  self.insert_random(self.length)
  return self.ask()
 #display the challenge
 def ask(self):
  print ' '.join(self.keys), ":", self.dictionary[self.secret_word] 
  print 
  return self.input_loop()
 #take input from the player
 def input_loop(self):
  #four self.mistakes are allowed
  chances = len(set(self.secret_word)) + 4   
  while chances != 0 and self.mistakes < 5:
   try:
    self.guess = raw_input("> ")
   except EOFError:
    exit(1)
   self.test_input()
   print ' '.join(self.keys)
   if '_' not in self.keys:
    print 'well done!'
    break
   chances -= 1
  if self.mistakes > 4: print 'the word was', ''.join(self.secret_word).upper()
  return self.quit_message()
 def quit_message(self):
  print "\n"
  print "Press 'c' to continue, or any other key to quit the game. "
  print "You can always quit the game by pressing 'Ctrl+D'"
  try:
   command = raw_input('> ')
   if command == 'c': return self.__init__() #loopback
   else : exit(0)
  except EOFError: exit(1)
if __name__ == '__main__':
 game = Hangman()
 game.__init__()

希望本文所述对大家的Python程序设计有所帮助。


本文地址:http://www.45fan.com/a/question/15258.html
Tags: 实现 python 简单
编辑:路饭网
关于我们 | 联系我们 | 友情链接 | 网站地图 | Sitemap | App | 返回顶部