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Shell脚本如何实现根据文件修改时间来归类?

2015-07-24 07:16:01 来源:www.45fan.com 【

Shell脚本如何实现根据文件修改时间来归类?

#!/bin/bash

# exctute
# ./mod.sh file_type input_folder output_folder
# ./mod.sh *.txt /tmp /data/

# paramater count 
if [ ! $# -eq 3 ]; then
 echo "[ERROR] error paramater."
 exit
fi

# file type
file_type="${1}"

# input foloder
if [ -d "${2}" ]; then 
 folder="${2}"
else
 echo "[ERROR] input folder is not exsit."
 exit 
fi

# output folder
if [ -d "${3}" ]; then
 output="${3}"
else
 echo "[ERROR] output folder is not exsit."
 exit
fi

# search file
find ${folder} -name "${file_type}" | while read filename ; 
do
 # file type
 file_type=`echo ${filename##*.}`

 # file size
 file_size=`stat "${filename}" | sed -n '2,1p' | awk '{print $2}' `
 # file modify time
 file_modify=`stat "${filename}" | sed -n '6,1p' | awk '{print $2, $3}' | sed -e 's/[-: ]//g' `

 # output folder 
 path="${output}/${file_modify:0:6}"
 if [ ! -d "${path}" ]; then
  mkdir -p ${path}
  echo "folder(${path}) is created . "
 fi

 # new file full name 
 new_file_name=`echo ${path}/${file_modify}_[${file_size}].${file_type}`

 if [ ! -f "${new_file_name}" ]; then
  mv "${filename}" "${new_file_name}"
 else
  echo "file(${new_file_name}) is exsit, can not be removed. "
 fi
done
echo "finished !"
exit

本文地址:http://www.45fan.com/a/question/15507.html
Tags: 实现 shell 脚本
编辑:路饭网
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