Lua编程示例(六):C语言调用Lua函数的方法
C++端：
#include "stdafx.h"
lua_State *L;
void load_lua(lua_State **L,char *filename){
*L=luaL_newstate();
luaL_openlibs(*L);
if(luaL_loadfile(*L,filename) || lua_pcall(*L,0,0,0)){
luaL_error(*L,"load file error! %s",lua_tostring(*L,-1));
}
}
int _tmain(int argc, _TCHAR* argv[])
{
load_lua(&L,"raw.lua"); //此处若直接传入L会出错
lua_getglobal(L,"gettable");
if(lua_pcall(L,0,1,0) !=0){
luaL_error(L,"pcall wrong %s",lua_tostring(L,-1));
}
luaL_checktype(L,1,LUA_TTABLE);
int n=lua_objlen(L,1);
printf("n = %d\n",n);
lua_pushstring(L,"ee");
lua_rawseti(L,1,5); //t[n]=v,n为第三个参数，v是栈顶元素
n=lua_objlen(L,1);
printf("n = %d\n",n);
int i;
for(i=1;i<=n;i++){
lua_rawgeti(L,1,i);
printf("%s\n",lua_tostring(L,-1));
}
return 0;
}
lua脚本：
function gettable()
tb={ "aa","bb","cc","dd"}
return tb
end
运行输出的结果为：
n = 4 n = 5 aa bb cc dd ee
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