javascript如何实现单选和多选、向右和向左移动？
本文实例讲述了基于javascript实现单选及多选的向右和向左移动实例。分享给大家供大家参考。具体实现方法如下：
方法 一：
<body>
<h1>实现单选及多选的向右和向左移动</h1>
<div id="lst">
<span>
<select id="lselect" size="10" multiple="multiple" style="width: 100px; background-color:blue;">
<option>选项1</option>
<option>选项2</option>
<option>选项3</option>
<option>选项4</option>
<option>选项5</option>
<option>选项6</option>
<option>选项7</option>
<option>选项8</option>
<option>选项9</option>
<option>选项10</option>
</select>
<span style="width: 200px;height: 100px;">
<input type="button" value="单个向右移动" onclick="oneRMove()" />
<input type="button" value="多个向右移动" onclick="moveRMove()" />
<input type="button" value="单个向左移动" onclick="oneLMove()" />
<input type="button" value="多个向左移动" onclick="moveLMove()" />
</span>
<span>
<select id="rselect" size="10" style="width: 100px;background-color: yellow;" multiple="multiple">
</select>
</span>
</span>
</div>
</body>
<script type="text/javascript">
window.onload = function(){}
//获取select对象
var lselect=document.getElementById("lselect");
var rselect=document.getElementById("rselect");
//获取lselect和roptions对象中的所有option
var loptions=lselect.options;
var roptions=rselect.options;
function oneRMove(){
for(var i=0;i<loptions.length;i++){
var op=loptions[i];
if(op.selected){
rselect.appendChild(op);
break;
}
}
}
function moveRMove(){
for(var i=0;i<loptions.length;i++){
var op=loptions[i];
if(op.selected){
rselect.appendChild(op);
i--;
}
}
}
function oneLMove(){
for(var i=0;i<roptions.length;i++){
var op=roptions[i];
if(op.selected){
lselect.appendChild(op);
break;
}
}
}
function moveLMove(){
for(var i=0;i<roptions.length;i++){
var op=roptions[i];
if(op.selected){
lselect.appendChild(op);
i--;
}
}
}
</script>
方法 二：
<script type="text/javascript">
sortitems = 1;
function move(fbox,tbox) {
for(var i=0; i<fbox.options.length; i++) {
if(fbox.options[i].selected && fbox.options[i].value != "") {
var no = new Option();
no.value = fbox.options[i].value;
no.text = fbox.options[i].text;
tbox.options[tbox.options.length] = no;
fbox.options[i].value = "";
fbox.options[i].text = "";
}
}
BumpUp(fbox);
if (sortitems) SortD(tbox);
}
function BumpUp(box) {
for(var i=0; i<box.options.length; i++) {
if(box.options[i].value == "") {
for(var j=i; j<box.options.length-1; j++) {
box.options[j].value = box.options[j+1].value;
box.options[j].text = box.options[j+1].text;
}
var ln = i;break;
}
}
if(ln < box.options.length) {
box.options.length -= 1;
BumpUp(box);
}
}
function SortD(box) {
var temp_opts = new Array();
var temp = new Object();
for(var i=0; i<box.options.length; i++) {
temp_opts[i] = box.options[i];
}
for(var x=0; x<temp_opts.length-1; x++) {
for(var y=(x+1); y<temp_opts.length; y++) {
if(temp_opts[x].text > temp_opts[y].text) {
temp = temp_opts[x].text;
temp_opts[x].text = temp_opts[y].text;
temp_opts[y].text = temp;
temp = temp_opts[x].value;
temp_opts[x].value = temp_opts[y].value;
temp_opts[y].value = temp;
}
}
}
for(var i=0; i<box.options.length; i++) {
box.options[i].value = temp_opts[i].value;
box.options[i].text = temp_opts[i].text;
}
}
</script>
</head>
<body>
<form ACTION="" METHOD="POST">
<table border="0">
<tr>
<td><select multiple size="5" name="list1">
<option value="l1">A</option>
<option value="l2">B </option>
<option value="l3">C</option>
<option value="l4">D</option>
</select></td>
<td>
<input type="button" value="向右" onclick="move(this.form.list1,this.form.list2)" name="B1"><br>
<input type="button" value="向左" onclick="move(this.form.list2,this.form.list1)" name="B2">
</td>
<td><select multiple size="5" name="list2">
<option value="r1">E</option>
<option value="r2">F </option>
<option value="r3">G</option>
<option value="r4">H</option>
</select></td>
</tr>
</table>
</form>
</body>
希望本文所述对大家的javascript程序设计有所帮助。
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